Case
Study – 04
In the picture given below, one can see a rectangular
in-ground swimming pool installed by a family in their backyard. There is a
concrete sidewalk around the pool of width x m. The outside edges of the
sidewalk measure 7m and 12m. The area of the pool is 36 sq. m.
(a)
Based on the information given above, form
a quadratic equation in terms of x.
(b)
Find the width of the sidewalk around the
pool.
Soln:
Given that Outside Edges of side walk
L = 12m
B = 7 m
Area of
the Pool = 36 cm2
Width of
the side walk = x m
(a)
Based on the information given above, form
a quadratic equation in terms of x.
Inner length of the pool =
(12 – 2x) m
Inner breadth of the pool
= (7 – 2x) m
Area of the pool = Length
x breadth
36 m = (12 – 2x) (7 – 2x)
36 = 84 – 24x + 4x2
– 14x
36 = 84 – 38x + 4x2
i.e., 4x2 – 38x + 84 – 36 = 0
The required quadratic
equation is
4x2 – 38x + 48 = 0
(b)
Find the width of the sidewalk around the
pool
Solve the above quadratic
equation
4x2 – 38x + 48 = 0
2x2 – 19x + 24 = 0
2x2 – 16x – 3x + 24 = 0
2x (x – 8) -3(x – 8) = 0
(2x – 3) (x – 8) = 0
i.e., (2x – 3) = 0 or (x
– 8) = 0
i.e., x = 3/2 or
x = 8
Width of the side walk 8m is not possible
Therefore, width of side
walk = 3/2 m
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